Coordination Compounds
π§ First, listen to the class discussion audio of Coordination Compounds:
π§ Real-Life Use of Coordination Compounds
Build a strong foundation on Coordination Compounds with real-life applications and practice session.
Ligands and Coordination Number
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Definition
A Ligand is a molecule or ion that can donate a pair of electrons to the central metal atom to form a coordinate covalent bond. The metal acts as a Lewis Acid (accepts electrons), and the ligand acts as a Lewis Base (donates electrons).
Explanation
Imagine the metal ion is a person with empty hands, and the ligands are friends offering a handshake. The "handshake" is the coordinate bond.
- Unidentate: Donate one electron pair (e.g., $\text{Cl}^-$, $\text{H}_2\text{O}$).
- Bidentate: Donate two electron pairs (e.g., oxalate ion, ethylenediamine).
- Polydentate: Donate multiple pairs (e.g., EDTA).
- Chelation: When a polydentate ligand binds to a metal, it forms a ring-like structure called a "chelate," enhancing stability.
Examples
- $\text{NH}_3$ (Ammonia) $\rightarrow$ Unidentate
- $\text{en}$ (ethylenediamine) $\rightarrow$ Bidentate
Real-Life Application: Water Softening
EDTA (a polydentate ligand) wraps around $\text{Ca}^{2+}$ and $\text{Mg}^{2+}$ ions in hard water like a claw, trapping them and preventing them from reacting with soap.
Coordination Number (CN)
The total number of coordinate bonds formed between the central metal ion and the ligands.
- $\text{[Pt(NH}_3)_4\text{]}^{2+} \rightarrow$ CN = 4
- $\text{[Co(NH}_3)_6\text{]}^{3+} \rightarrow$ CN = 6
Wernerβs Theory
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Definition
Alfred Werner proposed that metal ions in coordination compounds exhibit two types of valencies: Primary and Secondary.
Explanation
- Primary Valency: Corresponds to the oxidation state. It is ionizable and satisfied by negative ions. (Spherical arrangement).
- Secondary Valency: Corresponds to the coordination number. It is non-ionizable and defines the geometry of the molecule. (Fixed spatial arrangement).
Example
In $\text{CoCl}_3 \cdot 6\text{NH}_3$, Cobalt has a primary valency of 3 and a secondary valency of 6.
Real-Life Use: Analytical Chemistry
Allows chemists to predict how many ions a complex will release in water, helping in precipitation reactions with $\text{AgNO}_3$.
IUPAC Nomenclature
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The Rules
- Order: Name ligands first (alphabetical), then the metal.
- Ligand Names: $\text{H}_2\text{O}$ (aqua), $\text{NH}_3$ (ammine), $\text{Cl}^-$ (chlorido), $\text{CN}^-$ (cyanido).
- Prefixes: *di-, tri-, tetra-* for simple; *bis-, tris-* for complex ligands.
- Metal Name: If the complex is an anion, metal ends in "-ate" (e.g., Ferrate).
- Oxidation State: Written in Roman numerals in brackets, e.g., (III).
Examples
- $\text{[Co(NH}_3)_6\text{]Cl}_3 \rightarrow$ Hexaamminecobalt(III) chloride.
- $\text{K}_4\text{[Fe(CN)}_6\text{]} \rightarrow$ Potassium hexacyanidoferrate(II).
Isomerism
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Definition
Isomers are compounds with the same chemical formula but different arrangements of atoms.
1. Structural Isomerism
- Linkage: Different binding atoms (e.g., $\text{SCN}^-$ vs $\text{NCS}^-$).
- Ionization: Exchange of ligands between sphere and counter ion.
- Hydrate: Water molecules inside vs outside the sphere.
- Coordination: Exchange between cationic and anionic entities.
2. Stereoisomerism
- Geometrical: *Cis* (same side) and *Trans* (opposite side).
- Optical: Non-superimposable mirror images (Enantiomers).
Real-Life Use: Medicine (Cisplatin)
Cisplatin (cis-isomer of $\text{[Pt(NH}_3)_2\text{Cl}_2\text{]}$) is a powerful anti-cancer drug. Its isomer, Transplatin, is completely ineffective.
Bonding in Complexes: VBT and CFT
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Valence Bond Theory (VBT)
Explains hybridization based on coordination number:
- $sp^3$ $\rightarrow$ Tetrahedral
- $dsp^2$ $\rightarrow$ Square Planar
- $sp^3d^2$ or $d^2sp^3$ $\rightarrow$ Octahedral
Crystal Field Theory (CFT)
Suggests ligands split the five $d$-orbitals into two sets: $t_{2g}$ and $e_g$.
- Strong Field Ligands (SFL): Large splitting $\rightarrow$ Forced pairing $\rightarrow$ Low Spin.
- Weak Field Ligands (WFL): Small splitting $\rightarrow$ No pairing $\rightarrow$ High Spin.
Comparison Table: VBT vs. CFT
| Feature | Valence Bond Theory (VBT) | Crystal Field Theory (CFT) |
|---|---|---|
| Nature of Bond | Covalent (Hybridization) | Electrostatic (Ion-Dipole) |
| Orbital Focus | Hybrid orbitals | Splitting of d-orbitals |
| Color Explanation | Cannot explain color | Explains via d-d transitions |
| Magnetic Prediction | Based on unpaired electrons | Based on $\Delta_o$ and pairing energy |
Real-Life Use: Gemstones
The red color of rubies is due to $\text{Cr}^{3+}$ ions. The $\Delta_o$ gap allows the crystal to absorb green-blue light and reflect red.
Magnetic Properties and Color
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Color
Arises from d-d transitions. If $\text{d}^0$ or $\text{d}^{10}$, the compound is usually colorless.
Magnetic Moment ($\mu$)
($n = \text{unpaired electrons}$, $\text{BM} = \text{Bohr Magneton}$)
Numerical Problems
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Problem 1: Calculate the spin-only magnetic moment of $\text{[Fe(H}_2\text{O)}_6\text{]}^{3+}$.
Solution:
1. $\text{Fe}$ state: $+3 \rightarrow [\text{Ar}] 3\text{d}^5$.
2. $\text{H}_2\text{O}$ is WFL $\rightarrow$ no pairing $\rightarrow n = 5$.
3. $\mu = \sqrt{5(5+2)} = \sqrt{35} \approx 5.92 \text{ BM}$.
Problem 2: Find the hybridization of $\text{[Ni(CN)}_4\text{]}^{2-}$.
Solution:
1. $\text{Ni}$ state: $+2 \rightarrow [\text{Ar}] 3\text{d}^8$.
2. $\text{CN}^-$ is SFL $\rightarrow$ forces 2 unpaired electrons to pair up $\rightarrow$ one $3\text{d}$ orbital empty.
3. Hybridization: $3\text{d} + 2(3\text{s}) + 2(3\text{p}) = \text{dsp}^2$. Geometry: Square Planar.
Modern Tools and Industry Applications
π Industry Insights
- MRI Contrast Agents: Gadolinium ($\text{Gd}^{3+}$) complexes are used for high paramagnetism.
- Catalysis: Wilkinsonβs Catalyst $\text{[RhCl(PPh}_3)_3\text{]}$ for alkene hydrogenation.
- Waste Water: Chelating agents remove heavy metals like $\text{Pb}^{2+}$ and $\text{Hg}^{2+}$.
Case Study: Hemoglobin & CO Poisoning
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Hemoglobin contains an $\text{Fe}^{2+}$ ion coordinated to a porphyrin ring. One site is open for $\text{O}_2$ to bind.
The Conflict: Carbon Monoxide ($\text{CO}$) is a strong field ligand. It binds to $\text{Fe}^{2+}$ nearly 200 times more tightly than $\text{O}_2$ does.
The Result: $\text{CO}$ locks the hemoglobin, forming carboxy-hemoglobin and preventing oxygen transport, which leads to lethal poisoning. This demonstrates how ligand strength dictates biological survival.
Multiple Choice Questions
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- Which of the following is a bidentate ligand?
Ans: (c) $\text{ox}^{2-}$ - The coordination number of $\text{Co}$ in $\text{[Co(en)}_3\text{]Cl}_3$ is:
Ans: (b) 6 - Which theory explains the color of coordination complexes?
Ans: (c) CFT - A complex with $dsp^2$ hybridization is usually:
Ans: (c) Square Planar - Which ligand is the strongest?
Ans: (d) $\text{CN}^-$ - Optical isomerism is possible in:
Ans: (b) $\text{[Co(en)}_3\text{]}^{3+}$ - The magnetic moment of a $\text{d}^3$ system is approximately:
Ans: (b) 3.87 BM - In $\text{[Pt(NH}_3)_2\text{Cl}_2\text{]}$, the *trans* isomer is:
Ans: (b) Ineffective in cancer treatment - Which of the following is a "low spin" complex?
Ans: (b) $\text{[Fe(CN)}_6\text{]}^{4-}$ - The IUPAC name for $\text{[Ni(CO)}_4\text{]}$ is:
Ans: (a) Tetracarbonylnickel(0)
Exam-Oriented Questions with Answers
π Important Questions
- Q: Distinguish between a double salt and a complex salt.
Ans: Double salts dissociate completely into simple ions in water; complex salts do not. - Q: Why are most coordination compounds colored?
Ans: Due to d-d transitions caused by the splitting of d-orbitals (CFT). - Q: Explain the "Chelate Effect."
Ans: Polydentate ligands form ring structures which are significantly more stable than unidentate complexes. - Q: Difference between *fac* and *mer* isomers?
Ans: *Facial (fac)* ligands occupy one face of the octahedron; *meridional (mer)* ligands are around the meridian. - Q: Predict geometry of $\text{[Ni(CN)}_4\text{]}^{2-}$.
Ans: Square Planar ($dsp^2$) and diamagnetic. - Q: Why is $\text{[Ti(H}_2\text{O)}_6\text{]}^{3+}$ colored but $\text{[Sc(H}_2\text{O)}_6\text{]}^{3+}$ is colorless?
Ans: $\text{Ti}^{3+}$ is $\text{d}^1$ (transition possible), while $\text{Sc}^{3+}$ is $\text{d}^0$ (no electrons). - Q: Define Ambidentate ligands.
Ans: Ligands that can bind via two different atoms, e.g., $\text{NO}_2^-$ (N or O). - Q: Effect of oxidation state on $\Delta_o$?
Ans: Increasing oxidation state increases $\Delta_o$ due to stronger ligand attraction. - Q: IUPAC name of $\text{[Co(NH}_3)_5\text{Cl]Cl}_2$.
Ans: Pentaamminechloridocobalt(III) chloride. - Q: Why do strong field ligands lead to low spin?
Ans: Large $\Delta_o$ makes pairing energy lower than the jump to $e_g$ orbital.
Revision Notes & Memory Tricks
β‘ Quick Revision
- Spectrochemical Series: *"**I** **Br**ing **Cl**ean **F**lowers, **O**h $\text{H}_2\text{O}$ $\text{NH}_3$ **en** $\text{CN}$ $\text{CO}$"* (Weakest $\rightarrow$ Strongest).
- VBT Geometry Check:
- CN 4 + SFL = Square Planar
- CN 4 + WFL = Tetrahedral
- CN 6 = Octahedral